PSLE In the figure, KLN and QPN are straight lines and PL is parallel to NM. ∠PQK is a right angle, ∠QKL = 48°, ∠KLM = 119° and ∠NPL = 62°.
- Find ∠KLP.
- Find ∠LMN.
(a)
∠KNQ
= 180° - 90° - 48°
= 42° (Angles sum of triangle)
∠NLP
= 180° - 62° - 42°
= 76° (Angles sum of triangle)
∠KLP
= 180° - 76°
= 119° (Angles on a straight line)
(b)
∠NLM
= 360° - 119° - 76° - 119°
= 46° (Angles at a point)
∠LMN
= 180° - 46° - 46°
= 88°
Answer(s): (a) 119°; (b) 88°