PSLE In the figure, ABD and FED are straight lines and EB is parallel to DC. ∠EFA is a right angle, ∠FAB = 49°, ∠ABC = 111° and ∠DEB = 63°.
- Find ∠ABE.
- Find ∠BCD.
(a)
∠ADF
= 180° - 90° - 49°
= 41° (Angles sum of triangle)
∠DBE
= 180° - 63° - 41°
= 76° (Angles sum of triangle)
∠ABE
= 180° - 76°
= 111° (Angles on a straight line)
(b)
∠DBC
= 360° - 111° - 76° - 111°
= 62° (Angles at a point)
∠BCD
= 180° - 62° - 62°
= 56°
Answer(s): (a) 111°; (b) 56°