PSLE FGHJ is a rhombus. JLG and JKHM are straight lines.
- Find ∠FGJ.
- Find ∠JHM.
- Find ∠JLK.
(a)
∠FGJ
= (180° - 108°) ÷ 2
= 36° (Isosceles triangle)
(b)
∠GHJ
= ∠GFJ
= 108° (Rhombus)
∠JHM
= 180° - 108°
= 72° (Angles on a straight line)
(c)
∠KGL
= ∠FGL
= 36° (Rhombus)
∠GKL
= 180° - 66°
= 114° (Angles on a straight line)
∠JLK
= 36° + 114°
= 150° (Exterior angle of a triangle)
Answer(s): (a) 36° (b) 72° (c) 150°