PSLE TUVW is a rhombus. WYU and WXVZ are straight lines.
- Find ∠TUW.
- Find ∠WVZ.
- Find ∠WYX.
(a)
∠TUW
= (180° - 100°) ÷ 2
= 40° (Isosceles triangle)
(b)
∠UVW
= ∠UTW
= 100° (Rhombus)
∠WVZ
= 180° - 100°
= 80° (Angles on a straight line)
(c)
∠XUY
= ∠TUY
= 40° (Rhombus)
∠UXY
= 180° - 62°
= 118° (Angles on a straight line)
∠WYX
= 40° + 118°
= 158° (Exterior angle of a triangle)
Answer(s): (a) 40° (b) 80° (c) 158°