PSLE FGHJ is a rhombus. JLG and JKHM are straight lines.
- Find ∠FGJ.
- Find ∠JHM.
- Find ∠JLK.
(a)
∠FGJ
= (180° - 100°) ÷ 2
= 40° (Isosceles triangle)
(b)
∠GHJ
= ∠GFJ
= 100° (Rhombus)
∠JHM
= 180° - 100°
= 80° (Angles on a straight line)
(c)
∠KGL
= ∠FGL
= 40° (Rhombus)
∠GKL
= 180° - 62°
= 118° (Angles on a straight line)
∠JLK
= 40° + 118°
= 158° (Exterior angle of a triangle)
Answer(s): (a) 40° (b) 80° (c) 158°