PSLE HJKL is a rhombus. LNJ and LMKP are straight lines.
- Find ∠HJL.
- Find ∠LKP.
- Find ∠LNM.
(a)
∠HJL
= (180° - 108°) ÷ 2
= 36° (Isosceles triangle)
(b)
∠JKL
= ∠JHL
= 108° (Rhombus)
∠LKP
= 180° - 108°
= 72° (Angles on a straight line)
(c)
∠MJN
= ∠HJN
= 36° (Rhombus)
∠JMN
= 180° - 71°
= 109° (Angles on a straight line)
∠LNM
= 36° + 109°
= 145° (Exterior angle of a triangle)
Answer(s): (a) 36° (b) 72° (c) 145°