PSLE TUVW is a rhombus. WYU and WXVZ are straight lines.
- Find ∠TUW.
- Find ∠WVZ.
- Find ∠WYX.
(a)
∠TUW
= (180° - 110°) ÷ 2
= 35° (Isosceles triangle)
(b)
∠UVW
= ∠UTW
= 110° (Rhombus)
∠WVZ
= 180° - 110°
= 70° (Angles on a straight line)
(c)
∠XUY
= ∠TUY
= 35° (Rhombus)
∠UXY
= 180° - 62°
= 118° (Angles on a straight line)
∠WYX
= 35° + 118°
= 153° (Exterior angle of a triangle)
Answer(s): (a) 35° (b) 70° (c) 153°