PSLE TUVW is a rhombus. WYU and WXVZ are straight lines.
- Find ∠TUW.
- Find ∠WVZ.
- Find ∠WYX.
(a)
∠TUW
= (180° - 106°) ÷ 2
= 37° (Isosceles triangle)
(b)
∠UVW
= ∠UTW
= 106° (Rhombus)
∠WVZ
= 180° - 106°
= 74° (Angles on a straight line)
(c)
∠XUY
= ∠TUY
= 37° (Rhombus)
∠UXY
= 180° - 64°
= 116° (Angles on a straight line)
∠WYX
= 37° + 116°
= 153° (Exterior angle of a triangle)
Answer(s): (a) 37° (b) 74° (c) 153°