PSLE HJKL is a rhombus. LNJ and LMKP are straight lines.
- Find ∠HJL.
- Find ∠LKP.
- Find ∠LNM.
(a)
∠HJL
= (180° - 106°) ÷ 2
= 37° (Isosceles triangle)
(b)
∠JKL
= ∠JHL
= 106° (Rhombus)
∠LKP
= 180° - 106°
= 74° (Angles on a straight line)
(c)
∠MJN
= ∠HJN
= 37° (Rhombus)
∠JMN
= 180° - 63°
= 117° (Angles on a straight line)
∠LNM
= 37° + 117°
= 154° (Exterior angle of a triangle)
Answer(s): (a) 37° (b) 74° (c) 154°