PSLE CDEF is a rhombus. FHD and FGEJ are straight lines.
- Find ∠CDF.
- Find ∠FEJ.
- Find ∠FHG.
(a)
∠CDF
= (180° - 104°) ÷ 2
= 38° (Isosceles triangle)
(b)
∠DEF
= ∠DCF
= 104° (Rhombus)
∠FEJ
= 180° - 104°
= 76° (Angles on a straight line)
(c)
∠GDH
= ∠CDH
= 38° (Rhombus)
∠DGH
= 180° - 68°
= 112° (Angles on a straight line)
∠FHG
= 38° + 112°
= 150° (Exterior angle of a triangle)
Answer(s): (a) 38° (b) 76° (c) 150°