PSLE DEFG is a rhombus. GJE and GHFK are straight lines.
- Find ∠DEG.
- Find ∠GFK.
- Find ∠GJH.
(a)
∠DEG
= (180° - 110°) ÷ 2
= 35° (Isosceles triangle)
(b)
∠EFG
= ∠EDG
= 110° (Rhombus)
∠GFK
= 180° - 110°
= 70° (Angles on a straight line)
(c)
∠HEJ
= ∠DEJ
= 35° (Rhombus)
∠EHJ
= 180° - 68°
= 112° (Angles on a straight line)
∠GJH
= 35° + 112°
= 147° (Exterior angle of a triangle)
Answer(s): (a) 35° (b) 70° (c) 147°