PSLE QRST is a rhombus. TVR and TUSW are straight lines.
- Find ∠QRT.
- Find ∠TSW.
- Find ∠TVU.
(a)
∠QRT
= (180° - 102°) ÷ 2
= 39° (Isosceles triangle)
(b)
∠RST
= ∠RQT
= 102° (Rhombus)
∠TSW
= 180° - 102°
= 78° (Angles on a straight line)
(c)
∠URV
= ∠QRV
= 39° (Rhombus)
∠RUV
= 180° - 67°
= 113° (Angles on a straight line)
∠TVU
= 39° + 113°
= 152° (Exterior angle of a triangle)
Answer(s): (a) 39° (b) 78° (c) 152°