PSLE DEFG is a rhombus. GJE and GHFK are straight lines.
- Find ∠DEG.
- Find ∠GFK.
- Find ∠GJH.
(a)
∠DEG
= (180° - 106°) ÷ 2
= 37° (Isosceles triangle)
(b)
∠EFG
= ∠EDG
= 106° (Rhombus)
∠GFK
= 180° - 106°
= 74° (Angles on a straight line)
(c)
∠HEJ
= ∠DEJ
= 37° (Rhombus)
∠EHJ
= 180° - 71°
= 109° (Angles on a straight line)
∠GJH
= 37° + 109°
= 146° (Exterior angle of a triangle)
Answer(s): (a) 37° (b) 74° (c) 146°