PSLE Lee had 15 more one-dollar notes than ten-dollar notes at first. He exchanged $80 worth of ten-dollar notes for one-dollar notes. How many less ten-dollar notes than one-dollar notes did Lee have after the exchange?
Number |
$1 |
$10 |
Before |
1 u + 15 |
1 u |
Change |
+ 80 |
- 8 |
After |
1 u + 15 + 80 |
1 u - 8 |
Number of ten-dollar notes that Lee exchanged into one-dollar notes
= 80 ÷ 10
= 8
Number of one-dollar notes that Lee received from the exchange
= 80 ÷ 1
= 80
Number of less ten-dollar notes than one-dollar notes
= 15 + 80 + 8
= 103
Answer: 103