PSLE Jenson and Fred have the same total number of coins. Jenson has a number of fifty-cent coins and 48 five-cent coins. The total mass of his coins is 0.477 kg. Fred has a number of fifty-cent coins and 108 five-cent coins.
- Who has less money in coins? How much less? Give your answers in this format. (Eg Adam, $12)
- Each fifty-cent coin is 2.4 g heavier than each five-cent coin. What is the total mass of Fred's coins in kg?
(a)
Both boys have the same number of coins. Since Fred has more five-cent coins than Jenson, it means that Fred has less fifty-cent coins than Jenson. So Fred has less money.
Difference in the number of five-cent coins.
= 108 - 48
= 60
Difference in the value of 1 five-cent coin and 1 fifty-cent coin
= 50 - 5
= 45¢
Amount that Fred had less than Jenson
= 60 x 45
= 2700¢
= $27
(b)
Difference in the mass between 60 five-cent coins and 60 fifty-cent coins
= 60 x 2.4
= 144 g
= 0.144 kg
Total mass of Fred's coins
= 0.477 - 0.144
= 0.333 kg
Answer(s): (a) Jenson, $27; (b) 0.333 kg