PSLE Pierre and Michael have the same total number of coins. Pierre has a number of fifty-cent coins and 58 ten-cent coins. The total mass of his coins is 1.142 kg. Michael has a number of fifty-cent coins and 118 ten-cent coins.
- Who has more money in coins? How much more? Give your answers in this format. (Eg Adam, $12)
- Each fifty-cent coin is 3.3 g heavier than each ten-cent coin. What is the total mass of Michael's coins in kg?
(a)
Since Pierre has less ten-cent coins than Michael but both had the same number of coins, Pierre had more money.
Both boys have the same number of coins. Since Pierre has less ten-cent coins than Michael, it means that Pierre has more fifty-cent coins than Michael. So Pierre has more money.
Difference in the number of ten-cent coins.
= 118 - 58
= 60
Difference in the value of 1 ten-cent coin and 1 fifty-cent coin
= 50 - 10
= 40¢
Amount that Pierre had more than Michael
= 60 x 40
= 2400¢
= $24
(b)
Difference in the mass between 60 ten-cent coins and 60 fifty-cent coins
= 60 x 3.3
= 198 g
= 0.198 kg
Total mass of Michael's coins
= 1.142 - 0.198
= 0.944 kg
Answer(s): (a) Pierre, $24; (b) 0.944 kg