PSLE A box contained black balls and blue balls. 40% of the balls were blue. After some green balls were added to the box, 16% of the balls were blue. What percentage of the balls in the box were green?
|
Blue |
Black |
Green |
Total |
Before |
2 u |
3 u |
|
5 u |
Change |
|
|
+ ? |
|
After |
16% |
24% |
|
100% |
40% =
40100 =
25 The number of blue balls remains unchanged.
2 u → 16%
1 u → 16% ÷ 2 = 8%
3 u → 3 x 8 = 24%
Percentage of the balls in the box that were green
= 100% - 16% - 24%
= 60%
Answer(s): 60%