PSLE A box contained white balls and blue balls. 60% of the balls were blue. After some silver balls were added to the box, 24% of the balls were blue. What percentage of the balls in the box were silver?
|
Blue |
White |
Silver |
Total |
Before |
3 u |
2 u |
|
5 u |
Change |
|
|
+ ? |
|
After |
24% |
16% |
|
100% |
60% =
60100 =
35 The number of blue balls remains unchanged.
3 u → 24%
1 u → 24% ÷ 3 = 8%
2 u → 2 x 8 = 16%
Percentage of the balls in the box that were silver
= 100% - 24% - 16%
= 60%
Answer(s): 60%