PSLE A box contained white balls and green balls. 70% of the balls were green. After some red balls were added to the box, 42% of the balls were green. What percentage of the balls in the box were red?
|
Green |
White |
Red |
Total |
Before |
7 u |
3 u |
|
10 u |
Change |
|
|
+ ? |
|
After |
42% |
18% |
|
100% |
70% =
70100 =
710 The number of green balls remains unchanged.
7 u → 42%
1 u → 42% ÷ 7 = 6%
3 u → 3 x 6 = 18%
Percentage of the balls in the box that were red
= 100% - 42% - 18%
= 40%
Answer(s): 40%