PSLE A box contained gold balls and green balls. 60% of the balls were green. After some silver balls were added to the box, 27% of the balls were green. What percentage of the balls in the box were silver?
|
Green |
Gold |
Silver |
Total |
Before |
3 u |
2 u |
|
5 u |
Change |
|
|
+ ? |
|
After |
27% |
18% |
|
100% |
60% =
60100 =
35 The number of green balls remains unchanged.
3 u → 27%
1 u → 27% ÷ 3 = 9%
2 u → 2 x 9 = 18%
Percentage of the balls in the box that were silver
= 100% - 27% - 18%
= 55%
Answer(s): 55%