PSLE A box contained blue balls and grey balls. 60% of the balls were grey. After some black balls were added to the box, 12% of the balls were grey. What percentage of the balls in the box were black?
|
Grey |
Blue |
Black |
Total |
Before |
3 u |
2 u |
|
5 u |
Change |
|
|
+ ? |
|
After |
12% |
8% |
|
100% |
60% =
60100 =
35 The number of grey balls remains unchanged.
3 u → 12%
1 u → 12% ÷ 3 = 4%
2 u → 2 x 4 = 8%
Percentage of the balls in the box that were black
= 100% - 12% - 8%
= 80%
Answer(s): 80%