PSLE A box contained grey balls and white balls. 70% of the balls were white. After some black balls were added to the box, 63% of the balls were white. What percentage of the balls in the box were black?
|
White |
Grey |
Black |
Total |
Before |
7 u |
3 u |
|
10 u |
Change |
|
|
+ ? |
|
After |
63% |
27% |
|
100% |
70% =
70100 =
710 The number of white balls remains unchanged.
7 u → 63%
1 u → 63% ÷ 7 = 9%
3 u → 3 x 9 = 27%
Percentage of the balls in the box that were black
= 100% - 63% - 27%
= 10%
Answer(s): 10%