PSLE A box contained gold balls and red balls. 60% of the balls were red. After some silver balls were added to the box, 21% of the balls were red. What percentage of the balls in the box were silver?
|
Red |
Gold |
Silver |
Total |
Before |
3 u |
2 u |
|
5 u |
Change |
|
|
+ ? |
|
After |
21% |
14% |
|
100% |
60% =
60100 =
35 The number of red balls remains unchanged.
3 u → 21%
1 u → 21% ÷ 3 = 7%
2 u → 2 x 7 = 14%
Percentage of the balls in the box that were silver
= 100% - 21% - 14%
= 65%
Answer(s): 65%