PSLE A box contained red balls and pink balls. 40% of the balls were pink. After some black balls were added to the box, 12% of the balls were pink. What percentage of the balls in the box were black?
|
Pink |
Red |
Black |
Total |
Before |
2 u |
3 u |
|
5 u |
Change |
|
|
+ ? |
|
After |
12% |
18% |
|
100% |
40% =
40100 =
25 The number of pink balls remains unchanged.
2 u → 12%
1 u → 12% ÷ 2 = 6%
3 u → 3 x 6 = 18%
Percentage of the balls in the box that were black
= 100% - 12% - 18%
= 70%
Answer(s): 70%