PSLE A box contained silver balls and brown balls. 40% of the balls were brown. After some gold balls were added to the box, 20% of the balls were brown. What percentage of the balls in the box were gold?
|
Brown |
Silver |
Gold |
Total |
Before |
2 u |
3 u |
|
5 u |
Change |
|
|
+ ? |
|
After |
20% |
30% |
|
100% |
40% =
40100 =
25 The number of brown balls remains unchanged.
2 u → 20%
1 u → 20% ÷ 2 = 10%
3 u → 3 x 10 = 30%
Percentage of the balls in the box that were gold
= 100% - 20% - 30%
= 50%
Answer(s): 50%