PSLE The number of boys and girls taking part in a contest are in the ratio 7 : 4. These students are put into two teams. 40% of the boys and 10% of the girls are in Team K. The rest of the students are in Team L.
- What is the ratio of the number of students in Team L to Team K? Give your answer in the simplest form.
- The number of girls in Team K is more than 50. What is the smallest possible total number of students taking part in the contest?
Boys |
Girls |
70 u |
40 u |
Team K |
Team L |
Team K |
Team L |
28 u |
42 u |
4 u |
36 u |
(a)
Boys : Girls
7 : 4
70 : 40
Number of boys in Team K
= 40% x 70 u
=
40100 x 70 u
= 28 u
Number of boys in Team L
= 70 u - 28 u
= 42 u
Number of girls in Team K
= 10% x 40 u
=
10100 x 40 u
= 4 u
Number of girls in Team L
= 40 u - 4 u
= 36 u
Team K : Team L
42 + 36 : 28 + 4
78 : 32
(÷2)39 : 16
(b)
Number of girls in Team K = 4 u
Since the number of girls in Team K is 4 u, it must be multiple of 4.
Number of sets of 4
= 50 ÷ 4
= 12 r 2
Since the number of girls in Team K is more than 50, the number of sets must be 1 more than 12.
1 u = 12 + 1 = 13
Smallest possible number of students
= 70 u + 40 u
= 110 u
= 110 x 13
= 1430
Answer(s): (a) 39 : 16; (b) 1430