PSLE The number of girls and boys taking part in a contest are in the ratio 7 : 8. These pupils are put into two groups. 70% of the girls and 10% of the boys are in Group B. The rest of the pupils are in Group C.
- What is the ratio of the number of pupils in Group C to Group B? Give your answer in the simplest form.
- The number of boys in Group B is more than 60. What is the smallest possible total number of pupils taking part in the contest?
Girls |
Boys |
70 u |
80 u |
Group B |
Group C |
Group B |
Group C |
49 u |
21 u |
8 u |
72 u |
(a)
Girls : Boys
7 : 8
70 : 80
Number of girls in Group B
= 70% x 70 u
=
70100 x 70 u
= 49 u
Number of girls in Group C
= 70 u - 49 u
= 21 u
Number of boys in Group B
= 10% x 80 u
=
10100 x 80 u
= 8 u
Number of boys in Group C
= 80 u - 8 u
= 72 u
Group B : Group C
21 + 72 : 49 + 8
93 : 57
(÷3)31 : 19
(b)
Number of boys in Group B = 8 u
Since the number of boys in Group B is 8 u, it must be multiple of 8.
Number of sets of 8
= 60 ÷ 8
= 7 r 4
Since the number of boys in Group B is more than 60, the number of sets must be 1 more than 7.
1 u = 7 + 1 = 8
Smallest possible number of pupils
= 70 u + 80 u
= 150 u
= 150 x 8
= 1200
Answer(s): (a) 31 : 19; (b) 1200