PSLE BCDE is a trapezium with BC parallel to ED. BGC and FGE are straight lines and BF = FC. ∠FBE = 97°.
- Find ∠BEG.
- Find ∠CFG.
(a)
∠BEG
= 180° - 97° - 24°
= 59° (Angles sum of triangle)
(b)
∠BGE
= 74° (Alternate angles)
∠CBF
= 74° - 24°
= 50° (Exterior angle of a triangle)
∠CFG
= 180° - 50° - 50° - 24°
= 56° (Angles sum of triangle)
Answer(s): (a) 59°; (b) 56°