PSLE CDEF is a trapezium with CD parallel to FE. CHD and GHF are straight lines and CG = GD. ∠GCF = 93°.
- Find ∠CFH.
- Find ∠DGH.
(a)
∠CFH
= 180° - 93° - 29°
= 58° (Angles sum of triangle)
(b)
∠CHF
= 74° (Alternate angles)
∠DCG
= 74° - 29°
= 45° (Exterior angle of a triangle)
∠DGH
= 180° - 45° - 45° - 29°
= 61° (Angles sum of triangle)
Answer(s): (a) 58°; (b) 61°