PSLE ABCD is a trapezium with AB parallel to DC. AFB and EFD are straight lines and AE = EB. ∠EAD = 93°.
- Find ∠ADF.
- Find ∠BEF.
(a)
∠ADF
= 180° - 93° - 29°
= 58° (Angles sum of triangle)
(b)
∠AFD
= 69° (Alternate angles)
∠BAE
= 69° - 29°
= 40° (Exterior angle of a triangle)
∠BEF
= 180° - 40° - 40° - 29°
= 71° (Angles sum of triangle)
Answer(s): (a) 58°; (b) 71°