PSLE FGHJ is a trapezium with FG parallel to JH. FLG and KLJ are straight lines and FK = KG. ∠KFJ = 97°.
- Find ∠FJL.
- Find ∠GKL.
(a)
∠FJL
= 180° - 97° - 25°
= 58° (Angles sum of triangle)
(b)
∠FLJ
= 70° (Alternate angles)
∠GFK
= 70° - 25°
= 45° (Exterior angle of a triangle)
∠GKL
= 180° - 45° - 45° - 25°
= 65° (Angles sum of triangle)
Answer(s): (a) 58°; (b) 65°