PSLE ABCD is a trapezium with AB parallel to DC. AFB and EFD are straight lines and AE = EB. ∠EAD = 97°.
- Find ∠ADF.
- Find ∠BEF.
(a)
∠ADF
= 180° - 97° - 28°
= 55° (Angles sum of triangle)
(b)
∠AFD
= 65° (Alternate angles)
∠BAE
= 65° - 28°
= 37° (Exterior angle of a triangle)
∠BEF
= 180° - 37° - 37° - 28°
= 78° (Angles sum of triangle)
Answer(s): (a) 55°; (b) 78°