PSLE CDEF is a trapezium with CD parallel to FE. CHD and GHF are straight lines and CG = GD. ∠GCF = 98°.
- Find ∠CFH.
- Find ∠DGH.
(a)
∠CFH
= 180° - 98° - 27°
= 55° (Angles sum of triangle)
(b)
∠CHF
= 74° (Alternate angles)
∠DCG
= 74° - 27°
= 47° (Exterior angle of a triangle)
∠DGH
= 180° - 47° - 47° - 27°
= 59° (Angles sum of triangle)
Answer(s): (a) 55°; (b) 59°