Question
PSLE
EFGH is a trapezium with EF parallel to HG. EKF and JKH are straight lines and EJ = JF. ∠JEH = 91°.
  1. Find ∠EHK.
  2. Find ∠FJK.
3 m
(a)

Click button first when a symbol is required. X

(b)

Click button first when a symbol is required. X

PSLE
EFGH is a trapezium with EF parallel to HG. EKF and JKH are straight lines and EJ = JF. ∠JEH = 91°.
  1. Find ∠EHK.
  2. Find ∠FJK.