PSLE EFGH is a trapezium with EF parallel to HG. EKF and JKH are straight lines and EJ = JF. ∠JEH = 91°.
- Find ∠EHK.
- Find ∠FJK.
(a)
∠EHK
= 180° - 91° - 29°
= 60° (Angles sum of triangle)
(b)
∠EKH
= 69° (Alternate angles)
∠FEJ
= 69° - 29°
= 40° (Exterior angle of a triangle)
∠FJK
= 180° - 40° - 40° - 29°
= 71° (Angles sum of triangle)
Answer(s): (a) 60°; (b) 71°