PSLE FGHJ is a trapezium with FG parallel to JH. FLG and KLJ are straight lines and FK = KG. ∠KFJ = 95°.
- Find ∠FJL.
- Find ∠GKL.
(a)
∠FJL
= 180° - 95° - 23°
= 62° (Angles sum of triangle)
(b)
∠FLJ
= 73° (Alternate angles)
∠GFK
= 73° - 23°
= 50° (Exterior angle of a triangle)
∠GKL
= 180° - 50° - 50° - 23°
= 57° (Angles sum of triangle)
Answer(s): (a) 62°; (b) 57°