PSLE CDEF is a trapezium with CD parallel to FE. CHD and GHF are straight lines and CG = GD. ∠GCF = 94°.
- Find ∠CFH.
- Find ∠DGH.
(a)
∠CFH
= 180° - 94° - 25°
= 61° (Angles sum of triangle)
(b)
∠CHF
= 73° (Alternate angles)
∠DCG
= 73° - 25°
= 48° (Exterior angle of a triangle)
∠DGH
= 180° - 48° - 48° - 25°
= 59° (Angles sum of triangle)
Answer(s): (a) 61°; (b) 59°