PSLE BCDE is a trapezium with BC parallel to ED. BGC and FGE are straight lines and BF = FC. ∠FBE = 99°.
- Find ∠BEG.
- Find ∠CFG.
(a)
∠BEG
= 180° - 99° - 23°
= 58° (Angles sum of triangle)
(b)
∠BGE
= 65° (Alternate angles)
∠CBF
= 65° - 23°
= 42° (Exterior angle of a triangle)
∠CFG
= 180° - 42° - 42° - 23°
= 73° (Angles sum of triangle)
Answer(s): (a) 58°; (b) 73°