PSLE FGHJ is a trapezium with FG parallel to JH. FLG and KLJ are straight lines and FK = KG. ∠KFJ = 96°.
- Find ∠FJL.
- Find ∠GKL.
(a)
∠FJL
= 180° - 96° - 30°
= 54° (Angles sum of triangle)
(b)
∠FLJ
= 74° (Alternate angles)
∠GFK
= 74° - 30°
= 44° (Exterior angle of a triangle)
∠GKL
= 180° - 44° - 44° - 30°
= 62° (Angles sum of triangle)
Answer(s): (a) 54°; (b) 62°