PSLE CDEF is a trapezium with CD parallel to FE. CHD and GHF are straight lines and CG = GD. ∠GCF = 95°.
- Find ∠CFH.
- Find ∠DGH.
(a)
∠CFH
= 180° - 95° - 30°
= 55° (Angles sum of triangle)
(b)
∠CHF
= 70° (Alternate angles)
∠DCG
= 70° - 30°
= 40° (Exterior angle of a triangle)
∠DGH
= 180° - 40° - 40° - 30°
= 70° (Angles sum of triangle)
Answer(s): (a) 55°; (b) 70°