PSLE BCDE is a trapezium with BC parallel to ED. BGC and FGE are straight lines and BF = FC. ∠FBE = 96°.
- Find ∠BEG.
- Find ∠CFG.
(a)
∠BEG
= 180° - 96° - 22°
= 62° (Angles sum of triangle)
(b)
∠BGE
= 65° (Alternate angles)
∠CBF
= 65° - 22°
= 43° (Exterior angle of a triangle)
∠CFG
= 180° - 43° - 43° - 22°
= 72° (Angles sum of triangle)
Answer(s): (a) 62°; (b) 72°