PSLE BCDE is a trapezium with BC parallel to ED. BGC and FGE are straight lines and BF = FC. ∠FBE = 97°.
- Find ∠BEG.
- Find ∠CFG.
(a)
∠BEG
= 180° - 97° - 28°
= 55° (Angles sum of triangle)
(b)
∠BGE
= 69° (Alternate angles)
∠CBF
= 69° - 28°
= 41° (Exterior angle of a triangle)
∠CFG
= 180° - 41° - 41° - 28°
= 70° (Angles sum of triangle)
Answer(s): (a) 55°; (b) 70°