PSLE EFGH is a trapezium with EF parallel to HG. EKF and JKH are straight lines and EJ = JF. ∠JEH = 97°.
- Find ∠EHK.
- Find ∠FJK.
(a)
∠EHK
= 180° - 97° - 24°
= 59° (Angles sum of triangle)
(b)
∠EKH
= 67° (Alternate angles)
∠FEJ
= 67° - 24°
= 43° (Exterior angle of a triangle)
∠FJK
= 180° - 43° - 43° - 24°
= 70° (Angles sum of triangle)
Answer(s): (a) 59°; (b) 70°