PSLE EFGH is a trapezium with EF parallel to HG. EKF and JKH are straight lines and EJ = JF. ∠JEH = 95°.
- Find ∠EHK.
- Find ∠FJK.
(a)
∠EHK
= 180° - 95° - 30°
= 55° (Angles sum of triangle)
(b)
∠EKH
= 66° (Alternate angles)
∠FEJ
= 66° - 30°
= 36° (Exterior angle of a triangle)
∠FJK
= 180° - 36° - 36° - 30°
= 78° (Angles sum of triangle)
Answer(s): (a) 55°; (b) 78°