PSLE ABCD is a trapezium with AB parallel to DC. AFB and EFD are straight lines and AE = EB. ∠EAD = 91°.
- Find ∠ADF.
- Find ∠BEF.
(a)
∠ADF
= 180° - 91° - 28°
= 61° (Angles sum of triangle)
(b)
∠AFD
= 70° (Alternate angles)
∠BAE
= 70° - 28°
= 42° (Exterior angle of a triangle)
∠BEF
= 180° - 42° - 42° - 28°
= 68° (Angles sum of triangle)
Answer(s): (a) 61°; (b) 68°