PSLE FGHJ is a trapezium with FG parallel to JH. FLG and KLJ are straight lines and FK = KG. ∠KFJ = 91°.
- Find ∠FJL.
- Find ∠GKL.
(a)
∠FJL
= 180° - 91° - 27°
= 62° (Angles sum of triangle)
(b)
∠FLJ
= 73° (Alternate angles)
∠GFK
= 73° - 27°
= 46° (Exterior angle of a triangle)
∠GKL
= 180° - 46° - 46° - 27°
= 61° (Angles sum of triangle)
Answer(s): (a) 62°; (b) 61°