PSLE FGHJ is a trapezium with FG parallel to JH. FLG and KLJ are straight lines and FK = KG. ∠KFJ = 94°.
- Find ∠FJL.
- Find ∠GKL.
(a)
∠FJL
= 180° - 94° - 30°
= 56° (Angles sum of triangle)
(b)
∠FLJ
= 70° (Alternate angles)
∠GFK
= 70° - 30°
= 40° (Exterior angle of a triangle)
∠GKL
= 180° - 40° - 40° - 30°
= 70° (Angles sum of triangle)
Answer(s): (a) 56°; (b) 70°