PSLE BCDE is a trapezium with BC parallel to ED. BGC and FGE are straight lines and BF = FC. ∠FBE = 98°.
- Find ∠BEG.
- Find ∠CFG.
(a)
∠BEG
= 180° - 98° - 23°
= 59° (Angles sum of triangle)
(b)
∠BGE
= 66° (Alternate angles)
∠CBF
= 66° - 23°
= 43° (Exterior angle of a triangle)
∠CFG
= 180° - 43° - 43° - 23°
= 71° (Angles sum of triangle)
Answer(s): (a) 59°; (b) 71°