PSLE BCDE is a trapezium with BC parallel to ED. BGC and FGE are straight lines and BF = FC. ∠FBE = 94°.
- Find ∠BEG.
- Find ∠CFG.
(a)
∠BEG
= 180° - 94° - 30°
= 56° (Angles sum of triangle)
(b)
∠BGE
= 67° (Alternate angles)
∠CBF
= 67° - 30°
= 37° (Exterior angle of a triangle)
∠CFG
= 180° - 37° - 37° - 30°
= 76° (Angles sum of triangle)
Answer(s): (a) 56°; (b) 76°