PSLE The figure shows taps A and B and an empty tank. At 7 p.m., tap A was turned on. Water flowed into the tank from tap A at a rate of 3.6 litres per minute. After 7 minutes, tap B was turned on. At 7.15 p.m., the tank was half filled with water.
- How many litres of water flowed out of tap B in 1 minute?
- At 7.20 p.m., what fraction of the tank was filled with water?
(a)
Volume of the tank
= 60 x 35 x 20
= 42000 mℓ
= 42 ℓ
Volume of the tank at 7.15 p.m. when it was half filled with water
= 42 ÷ 2
= 21 ℓ
Volume of water by Tap A for 7 min
= 7 x 3.6
= 25.2 ℓ
Duration that Tap B was turned
= 15 - 7
= 8 min
Since there was a decrease in the volume of water in the tank, water flowed out of Tap B at a faster rate than that of Tap A.
Volume of water that flowed out in 8 min
= 25.2 - 21
= 4.2 ℓ
Volume of water that flowed out in 1 min
= 4.2 ÷ 8
= 0.525 ℓ
Volume of water that flowed out of Tap B in 1 min
= 3.6 + 0.525
= 4.125 ℓ
(b)
Duration from 7.15 p.m. to 7.20 p.m. = 5 min
Volume of water that flowed out from 7.15 p.m. to 7.20 p.m.
= 5 x 0.525
= 2.625 ℓ
Volume of water left at 7.20 p.m.
= 21 - 2.625
= 18.375 ℓ
Fraction of the tank filled with water at 7.20 p.m.
=
18.37542 =
716
Answer(s): (a) 4.125 ℓ; (b) 716