PSLE The figure shows taps A and B and an empty tank. At 7 p.m., tap A was turned on. Water flowed into the tank from tap A at a rate of 3.3 litres per minute. After 7 minutes, tap B was turned on. At 7.13 p.m., the tank was half filled with water.
- How many litres of water flowed out of tap B in 1 minute?
- At 7.29 p.m., what fraction of the tank was filled with water?
(a)
Volume of the tank
= 60 x 35 x 20
= 42000 mℓ
= 42 ℓ
Volume of the tank at 7.13 p.m. when it was half filled with water
= 42 ÷ 2
= 21 ℓ
Volume of water by Tap A for 7 min
= 7 x 3.3
= 23.1 ℓ
Duration that Tap B was turned
= 13 - 7
= 6 min
Since there was a decrease in the volume of water in the tank, water flowed out of Tap B at a faster rate than that of Tap A.
Volume of water that flowed out in 6 min
= 23.1 - 21
= 2.1 ℓ
Volume of water that flowed out in 1 min
= 2.1 ÷ 6
= 0.35 ℓ
Volume of water that flowed out of Tap B in 1 min
= 3.3 + 0.35
= 3.65 ℓ
(b)
Duration from 7.13 p.m. to 7.29 p.m. = 16 min
Volume of water that flowed out from 7.13 p.m. to 7.29 p.m.
= 16 x 0.35
= 5.6 ℓ
Volume of water left at 7.29 p.m.
= 21 - 5.6
= 15.4 ℓ
Fraction of the tank filled with water at 7.29 p.m.
=
15.442 =
1130
Answer(s): (a) 3.65 ℓ; (b) 1130